function data(){
var dataval = anyValue;
var myVar = setInterval(function(){computeData()});
function computeData(){
//inside this function there will be computations
//where dataval is included
}
}
This is just an example. My problem is that when I update the value of dataval and call the data(), the value is not updated inside the setInterval function. Unless I change the value again and call data(). But that is not even working well.
anyValue = 10
//the computation works
//if i update it to decreasingly, anyValue = 9, //it still uses the value 10,
//then if i use anyValue = 8, now it uses the value 9
This is not the code I am using. But same logic. Thanks! I hope you get my question! `
将您的计算数据函数computeData(object)
data()
之外,并使其接受变量,例如computeData(object)
然后将所需的对象通过var myVar = setInterval(function(){computeData(dataval)});
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