PHP call super parent method

Question

I'm not sure at all if there is such a term but here is what I want to do

class A {
    function a($a) {
        return $a;
    }
}

class B extends A {
    function a($a) {
        return parent::a('B' . $a);
    }
}

class C extends B {
    function a($a) {
        return superparent::a('C' . $a);
    }
}

$c = new C();
echo $c->a('C'); // "CC"

I want to bypass all medial classes and call the function on the parent where it was defined for the first time - is this possible?

Answer 1

No, and it's a terrible idea. All your class C knows is that it extends B . It cannot know nor should it know what, if anything, B extends. C cannot count on B extending anything, nor should it be aware of specific methods of that grand parent and their implementation details. You may be refactoring B tomorrow to extend another class, or to extend no class at all. Code would start breaking left and right if you established such three-class-crossover dependencies.

Classes should only interact with peers they're directly associated with, either through inheritance or dependency injection.

Just logically speaking: B adds something necessary to the behaviour of A to "make it a B ", and C adds something to make it a C . C builds on B , so anything B does C should do as well. Having C "jump over" B back to A suggests that your logic and responsibility assignment is mixed up in your class hierarchy.

Answer 2

Despite of any Engineering Software complaint (what you are trying to do is something that must be achieved by some other approach) I thought that my both examples were suposed to work:

Using trait:

<?php

trait Bypass_trait {
    public function super_ref() {
        return parent::super_ref();
    }
}

class A {
    function a($a) {
        return $a;
    }

    function super_ref() {
      return $this;
    }
}

class B extends A {
    use Bypass_trait;

    function a($a) {
        return $this->super_ref()->a('B' . $a);
    }
}

class C extends B {
    use Bypass_trait;

    function a($a) {
        return $this->super_ref()->a('C' . $a);
    }
}

$c = new C();
echo $c->a('C'); // "CC"

Using interface:

<?php

interface Bypass {
  public function super_ref();
}

class A implements Bypass {
    function a($a) {
        return $a;
    }

    function super_ref() {
      return $this;
    }
}

class B extends A implements Bypass {
    function a($a) {
        return $this->super_ref()->a('B' . $a);
    }

    function super_ref() {
      return parent::super_ref();
    }
}

class C extends B implements Bypass {
    function a($a) {
        return $this->super_ref()->a('C' . $a);
    }

    function super_ref() {
      return parent::super_ref();
    }
}

$c = new C();
echo $c->a('C'); // "CC"

Answer 3

我可以将“ A”抽象为东西，然后让b和c覆盖它

Answer 4

You can choose which parent method you call with A::a('C' . $a) .

When calling a parent function like this, it does not call it statically, just like parent::a() .