I am trying to convert a google doc into a bitmap so I can perform OCR within it. I am however getting the errors:
E/BitmapFactory: Unable to decode stream: java.io.FileNotFoundException: /document/acc=4;doc=14882: open failed: ENOENT (No such file or directory)
E/ReadFile: Bitmap must be non-null
E/CropTest: Failed to read bitmap
Code:
/**
* Fires an intent to spin up the "file chooser" UI and select an image.
*/
public void performFileSearch(View view) {
// ACTION_OPEN_DOCUMENT is the intent to choose a file via the system's file
// browser.
Intent intent = new Intent(Intent.ACTION_OPEN_DOCUMENT);
// Filter to only show results that can be "opened", such as a
// file (as opposed to a list of contacts or timezones)
intent.addCategory(Intent.CATEGORY_OPENABLE);
// Filter to show only images, using the image MIME data type.
// If one wanted to search for ogg vorbis files, the type would be "audio/ogg".
// To search for all documents available via installed storage providers,
// it would be "*/*".
intent.setType("application/vnd.google-apps.document");
startActivityForResult(intent, READ_REQUEST_CODE);
}
@Override
public void onActivityResult(int requestCode, int resultCode, Intent resultData){
if(requestCode == READ_REQUEST_CODE && resultCode == Activity.RESULT_OK){
Uri uri = null;
if(resultData != null){
uri = resultData.getData();
Log.i(TAG, "Uri" + uri.toString());
Toast.makeText(MainActivity.this, "Uri:" + uri.toString(), Toast.LENGTH_LONG).show();
IMGS_PATH = Environment.getExternalStorageDirectory().toString()+ "/TesseractSample/imgs";
prepareDirectory(IMGS_PATH);
prepareTesseract();
startOCR(uri);
}
}
}
//Function that begins the OCR functionality.
private void startOCR(Uri imgUri) {
try {
Log.e(TAG, "Inside the startOCR function");
BitmapFactory.Options options = new BitmapFactory.Options();
// 1 - means max size. 4 - means maxsize/4 size. Don't use value <4, because you need more memory in the heap to store your data.
options.inSampleSize = 4;
// FileOutputStream outStream = new FileOutputStream(String.valueOf(imgUri));
Bitmap bm = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imgUri);
// bm.compress(Bitmap.CompressFormat.PNG,100,outStream);
Bitmap bitmap = BitmapFactory.decodeFile(imgUri.getPath());
// bitmap = toGrayscale(bitmap);
//The result variable will hold whatever is returned from "extractText" function.
result = extractText(bm);
//Creating the intent to go to the CropTest
Intent intentToCropTest = new Intent(MainActivity.this, CropTest.class);
intentToCropTest.putExtra("result",result);
startActivity(intentToCropTest);
//Setting the string result to the content of the TextView.
// textView.setText(result);
} catch (Exception e) {
Log.e(TAG, e.getMessage());
}
}
You are trying to treat Android Uri
as file path. Don't do that. Instead retrive a ContentResolver instance and use it to convert Uri to stream:
AssetFileDescriptor fd = context.getContentResolver()
.openAssetFileDescriptor(uri, "r");
InputStream is = fd.createInputStream();
If AssetFileDescriptor is not supported (you get null or an Exception happens), try a more direct route:
InputStream is = context.getContentResolver().openInputStream();
There is also another super-duper powerful content-type-aware approach, which existed for ages, but was re-discovered by Google's own developers around the time of Android N release . It requires a lot more infrastructure on ContentProvider side (may not be supported in older versions of Google Services):
ContentResolver r = getContentResolver();
String[] streamTypes = r.getStreamTypes(uri, "*/*");
AssetFileDescriptor descriptor = r.openTypedAssetFileDescriptor(
uri,
streamTypes[0],
null);
InputStream is = descriptor.createInputStream();
Then use obtained stream to create Bitmap:
Bitmap bitmap = BitmapFactory.decodeStream(is);
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