array values not same after initializing

Question

I have written a piece of code in C language in which I am initializing an array with random numbers/characters. But when I print the array values after initializing it, I see that value on every index is equal to last assigned value (value of last index). Kindly tell what is the problem in my code?

Code:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>


int main () {

    char *save[3][3] = { {" "," "," "}, {" "," "," "}, {" "," "," "} };
    char x[2] = {'\0', '\0'};
    int i, j, b;
    srand(time(NULL));

    printf("Assigned Values (initializing):\n");
    for(i=0; i<3; i++) {
        for(j=0; j<3; j++) {
            b = rand()%10;
            x[0] = b+'0';
            save[i][j] = x;
            printf("%s ",save[i][j]);
        }
    }

    printf("\n\nValues after initializing:\n");
    for(i=0; i<3; i++) {
        for(j=0; j<3; j++) {
            printf("%s ",save[i][j]);
        }
    }

    printf("\n\n");
    return 0;
}

Output:

Assigned Values (initializing):
1 5 9 8 5 7 5 4 1

Values after initializing:
1 1 1 1 1 1 1 1 1

Press any key to continue . . .

Answer 1

You initialized all elements of elements of the array save to the same pointer, so what you can see using any of them will be same.

In this case, I suggest you should store the data directly in save like this:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>


int main (void) {

    char save[3][3][2] = { {" "," "," "}, {" "," "," "}, {" "," "," "} };
    int i, j, b;
    srand(time(NULL));

    printf("Assigned Values (initializing):\n");
    for(i=0; i<3; i++) {
        for(j=0; j<3; j++) {
            b = rand()%10;
            save[i][j][0] = b+'0';
            printf("%s ",save[i][j]);
        }
    }

    printf("\n\nValues after initializing:\n");
    for(i=0; i<3; i++) {
        for(j=0; j<3; j++) {
            printf("%s ",save[i][j]);
        }
    }

    printf("\n\n");
    return 0;
}