Finding unique arrays in the most efficient method

Question

I have the following arrays,

var a = [1,2,3,4,5];
var b = [2,3,4,5,6];
var c = [4,5,6,7,8];
var d = [1,2,3,4,5];

What is the most efficient way to find out the arrays that are distinct? Ie array a, b and c are distinct, where the order matters.

Answer 1

You can use Array.prototype.every() to compare arrays with Javascript

var a = [1,2,3,4,5];
var b = [2,3,4,5,6];

var is_same = (a.length == b.length) && a.every(function(element, index) {
return element === b[index]; 
});

Answer 2

One interesting way would be to convert them to String and Compare them. You could JSON stringify them or just join them like this

a.join('') === b.join('')

This works just because you say the order matters. I don't know the benchmarks between using JSON's stringify over join primitive. Maybe you could try that.

Answer 3

这也可以这样做

a.toString() === b.toString()