Array_filter to unset value from array

Question

I don't want to use foreach loop in my code and to unset array element from the array so I tried below code but it is not working as expected.

<?php 
$arr = array(array('0'=>'test','1'=>'test1','images'=>'data'),array('0'=>'test','1'=>'test1','images'=>'data'),array('0'=>'test','1'=>'test1','images'=>'data'),array('0'=>'test','1'=>'test1','images'=>'data'));
$arr1 = array_filter($arr,function ($item) use ($my_value) {    
    if(array_key_exists('images',$item)) {unset($item['images']);}
    return $item;});
    echo "<pre>";
    print_r($arr1);
    echo "</pre>";
    die;

I want to remove key 'images' from the array but this code returns actual array.

What is the error in this code?

Answer 1

Use array_map() instead of using array_filter ,

The array_map() will map each value of your array and create a new array with new values with new operations performed.

 $arr1 = array_map(function($tmp) { unset($tmp['images']); return $tmp; }, $arr);

Here is a Reference Link for array_map() .

Answer 2

You can use array_map() instead of array_filter()

$arr1 = array_map(function($tmp) { unset($tmp['images']); return $tmp; }, $arr); 

print_r($arr1);

Answer 3

You can do this by updating existing array without assigning new array

You can use this:

array_walk($ararray_walk($arr, function(&$v, $k) { // Pass the values by reference
    if(array_key_exists('images', $v)){
        unset($v['images']);
    }
});
print_r($arr);

Demo