function name cast to uint32_t

Question

I cannot understand this part of code can someone explain me what is going on?

I got a 2 functions:

void timer_irq_handler(void) {
   ....
}

void NVIC_SetVector(IRQn_Type IRQn, uint32_t vector) {
   ....
}

then I got something like this:

NVIC_SetVector(TIM_MST_IRQ, (uint32_t)timer_irq_handler);

I don't understand to cast void function to (uint32_t)

Answer 1

函数名称是一个指针，将指针转换为uint32_t在C语言中很好。