I'm trying to make a simple form that can be stored on mysql database. Whenever I try to connect it won't let me. Here's what I have:
PHP:
<?php
define('DB_NAME', 'forms1');
define('DB_USER', 'root');
define('DB_PASSWORD', 'root');
define('DB_HOST', 'localhost');
$link = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD);
if (!$link) {
die('Could not connect: ' . mysqli_error());
}
$db_selected = mysqli_select_db(DB_NAME, $link);
if (!$db_selected) {
die('Can\'t use ' . DB_NAME . ': ' . mysqli_error());
}
$value = $_POST['input1'];
$value2 = $_POST['input2'];
$sql = "INSERT INTO demo (input1, input2) VALUES ('$value', '$value2')";
if (!mysqli_query($sql)) {
die('Error: ' . mysqli_error());
}
mysqli_close();
?>
HTML:
<form action="demo.php" method="post" />
<p>Input 1: <input type="text" name="input1" /></p>
<p>Input 2: <input type="text" name="input2" /></p>
<input type="submit" value="Submit" />
</form>
I the correct credentials, but when I open up my page it says this, "Can't use forms1:"
Doesn't even give me the error.
It will give you an error message if you add the connection variable to the call to mysqli_error()
if (!$db_selected) {
die('Can\'t use ' . DB_NAME . ': ' . mysqli_error($link));
}
This applied to all calls to mysqli_error($link)
This mistake should have generated a PHP error, so if you did not see that I assume you are developing on a LIVE server where error reporting is turned off. In that case you should start all your scripts like this
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
This will ensure that you see these errors on the browser! Once a script is debugged you should probably remove these lines as you dont want a user to see this information should something go wrong while it is a LIVE site
Also the connect should contain the database name,
<?php
define('DB_NAME', 'forms1');
define('DB_USER', 'root');
define('DB_PASSWORD', 'root');
define('DB_HOST', 'localhost');
$link = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD,DB_NAME);
if (!$link) {
die('Could not connect: ' . mysqli_error());
}
//$db_selected = mysqli_select_db(DB_NAME, $link);
//if (!$db_selected) {
// die('Can\'t use ' . DB_NAME . ': ' . mysqli_error());
//}
The mysqli_select_db()
call is there so you can change to another database on the same connection if you were using 2 databases for some reason.
I assume you are converting from the
mysql_
API tomysqli_
API unfortunately the convertion is not a one to one conversion.
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