I have two tables: departments (20 departments) and tickets (lets say 1000 tickets). Each ticket is assigned to one department. I wanted to know how many tickets are assigned to each department.
[SOLVED] thank to the kind tip from frz3993
for the sake of completing the thread with the working result, at bottom you find my new script
I succeeded in that with these two queries.
The former loads the departments.
For the latter, I have used SELECT COUNT
for how many tickets for the current department.
PHP
<?php
$mysqli = new mysqli("localhost", "root", "*****", "tickets");
$openticket = null;
/* check connection */
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
$query = "SELECT id, name FROM dept ORDER BY id ASC"; // loads all the departmentes and their id
if ($result = $mysqli->query($query)) {
while ($row = $result->fetch_assoc()) {
//echo $row["id"] . " " . $row["name"] . "<br>"; // test point
$sqlcounttickets = "SELECT COUNT(dept_id) FROM ticket WHERE (dept_id=" . $row["id"] . " AND status!=1)"; // count how manytickets for that department id , IF status 1, skip, since ticket is closed
//echo $sqlcounttickets; // test point
$result2 = $mysqli->query($sqlcounttickets); //execute second query and get the result of the SELECT COUNT
//if ($mysqli->error) { //test point
// die($mysqli->error);
//} // no errors
$rowdue = $result2->fetch_row();
if ($rowdue[0] > 0){
echo "DeptLabelNum: " . $row["id"] . " - DeptName: " . $row["name"] . " " . $rowdue[0] ."<br>";
}
$openticket=$openticket+$rowdue[0];
}
/* free result set */
$result->free();
}
echo "<br>" . "Open Tickets: " . $openticket;
/* close connection */
$mysqli->close();
?>
the output is obviously unsorted since the tickets amount for department is random
DeptLabelNum: 0 - DeptName: Global (All Departments) 1
DeptLabelNum: 1 - DeptName: LCD 1
DeptLabelNum: 2 - DeptName: Smartphones 6
DeptLabelNum: 4 - DeptName: Pendrive 4
DeptLabelNum: 6 - DeptName: Plasma 7
DeptLabelNum: 22 - DeptName: HDD 1
DeptLabelNum: 23 - DeptName: Notebook 8
DeptLabelNum: 24 - DeptName: Tablet 12
Open Tickets: 40
You may bet on it :-) , I'd like to sort the output in descending order
So Tablet should be the first with 12 tickets second notebook with 8 tickets 3rd plasma
and so on
Do you suggest to load the output of the cycle into a MySQL temporary table?
Or would you use an PHP array?
Or it can be done with a more effective query?
Thank you for any help and suggestion since I am confuse with any of the three
R.
PS SOLUTION - the new script with one query only this is the new script which encloses in an html table the result.
PHP
/* check connection */
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
echo '<table>'."\xA";
$query = "
SELECT COUNT( ticket.id ) AS ticket_count, dept.id, dept.name
FROM ticket
LEFT JOIN dept ON ticket.dept_id = dept.id
WHERE ticket.status !=1
GROUP BY dept.id
ORDER BY ticket_count DESC";
if ($result = $mysqli->query($query)) {
while ($row = $result->fetch_assoc()) {
echo "\t" . "<tr><th>" . $row["name"] . "</th><th>" . $row["ticket_count"] . "</th></tr>". "\xA";
$openticket=$openticket+$row["ticket_count"];
}
/* free result set */
$result->free();
}
echo "\t" . "<tr><th></th><th></th></tr>". "\xA";
echo "\t" . "<tr><th>" . "Open Tickets: " . "</th><th>" . $openticket . "</th></tr>". "\xA";
echo "</table>". "\xA";
/* close connection */
$mysqli->close();
?>
You can do it by one query. Also, to be sure you get the list of all departments even there is no tickets for them:
SELECT d.*,tmp.ticket_count FROM departments d
LEFT JOIN (SELECT count(*) AS ticket_count, department_id FROM tickets GROUP by department_id) tmp
ON d.id = tmp.department_id
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