How to programatically detect if code is running in nuitka compiled or python interpreted mode

Question

Can anyone say how to detect if code is running in an exe created by Nuitka or in a normal python interpreter?

I think I would ideally like an " is_nuitka " flag that would be set to True when compiled and presumably not exist at all when not compiled.

Could then use code like this:

if '__is_nuitka__' in locals() or '__is_nuitka__' in globals():
    print('debug info: running in nuitka mode')

Any suggestions? Is there anything like this available? any alternative approaches?

Answer 1

从Nuitka 0.6.2开始，您可以使用以下代码：

is_nuitka = "__compiled__" in globals()

Answer 2

The first idea is to check sys.argv[0] like

if '.exe' in sys.argv[0]:
    # compiled