Reading variables from config file in Shell

Question

I have question about Linux shell scripts. My question is realy abstract, so may not make sense. The idea is having 1 script and 2 config files.

Script can be like (drinkOutput.sh):

#!/bin/bash

echo -e " $1 \n"
echo -e " $2 \n"

First Config file contain (beer.conf):

drink1="heineken"
drink2="argus"

Second Config file contain (vine.conf):

drink1="chardonnay"
drink2="hibernal"

The key thing is calling the script. It has to be in next format (or with parameter)

./drinkOutput.sh beer.conf 

In this case I need to have in $1 heineken and in $2 argus (inside of drinkOutput script). For

./drinkOutput.sh vine.conf 

I need to get back into drinkOutput.sh chardonnay and hibernal.

Does anybody know? Thanks for any tips

Answer 1

You can source the config files if they are in the right format (and it seems it is in your example).

drinkOutput()
{
    echo "$1"
    echo "$2"
}

conf="$1"
source "$conf"
drinkOutput "$drink1" "$drink2"

Answer 2

If is possible if your script calls itself with the proper arguments after having parsed them from the conf file:

if [ $# == 2 ] ; then
   # The arguments are correctly set in the sub-shell.
   # 2 arguments: do something with them
   echo magic happens: $1 $2

elif [ $# == 1 ] ; then
   # 1 argument: conf file: parse conf file
   arg1=`sed -n -e 's#drink1="\(.*\)"#\1#p' $1`
   arg2=`sed -n -e 's#drink2="\(.*\)"#\1#p' $1`
   $0 $arg1 $arg2
else
    # error
    echo "wrong args"
fi

test:

$ drinkOutput.sh beer.conf
magic happens: heineken argus