Looping through nested json object

Question

I have a badly designed JSON object which unfortunately I cannot change at this moment which contains a number of objects. Here is an example of what I am working with:

var land = [
    {"name":"city","value":"Los Angeles"},
    {"name":"state","value":"California"},
    {"name":"zip","value":"45434"},
    {"name":"country","value":"USA"}
];

Here is how I am looping through i:

$(document).ready(function(){
    $.each(land, function(key,value) {
      $.each(value, function(key,value) {
          console.log(key + ' : ' + value);
      })
    }); 
})

The result is as follows:

name : city
value : Los Angeles
name : state
value : California
name : zip
value : 45434
name : country
value : USA

My goal is to have a result like this:

city : Los Angeles
state : California
zip : 45434
country: USA

What am I missing here? How do I achieve my intended result? Thank you in advance :)

Answer 1

You can do it using ecmascript 5's forEach method:

land.forEach(function(entry){ 
      console.log(entry.name + " : " + entry.value) 
} );

or use jquery to support legacy web browsers:

$.each(land,function(index,entry) {
     console.log(entry.name + " : " + entry.value)
});

Answer 2

Don't loop through the subobject, just show its properties.

 var land = [{ "name": "city", "value": "Los Angeles" }, { "name": "state", "value": "California" }, { "name": "zip", "value": "45434" }, { "name": "country", "value": "USA" }]; $.each(land, function(index, object) { console.log(object.name, ": ", object.value); }) 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> 

Answer 3

If property names are same in all object( name and value ) then do it like.

$.each(land, function(key,value) {
  console.log(value.name + ' : ' + value.value);
}); 

Answer 4

You only need one forEach() loop to get this result.

 var land = [{ "name": "city", "value": "Los Angeles" }, { "name": "state", "value": "California" }, { "name": "zip", "value": "45434" }, { "name": "country", "value": "USA" }]; land.forEach(function(e) { console.log(e.name + ' : ' + e.value); }) 

Answer 5

Don't iterate through objects. You need only single loop to achieve this.

  $(document).ready(function(){ $.each(land, function(key,value) { console.log(value.name + ' : ' + value.value); }); }) 

Answer 6

var converter = function(object){
    return {city: object[0].value,
           state: object[1].value,
           zip: object[2].value,
           country: object[3].value
    }
}

converter(land)

Object { city: "Los Angeles", state: "California", zip: "45434", country: "USA" }