Map servlet programmatically instead of using web.xml or annotations

Question

How can I implement this mapping programmatically without web.xml or annotations? The mission is not to use any framework like spring or something else.

<servlet>
    <servlet-name>hello</servlet-name>
    <servlet-class>test.HelloServlet</servlet-class>
</servlet>
<servlet-mapping>
    <servlet-name>hello</servlet-name>
    <url-pattern>/hello</url-pattern>
</servlet-mapping>

Answer 1

You can use annotations to achieve this using code.

import java.io.IOException;

import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

@WebServlet("/hello")
public class HelloServlet extends HttpServlet {
    public void doGet(HttpServletRequest request, HttpServletResponse response)
        throws IOException {
        response.getWriter().println("Hello");
    }
}

You can read about annotations here , here and here

Answer 2

Since Servlet 3.0 you can use ServletContext#addServlet() for this.

servletContext.addServlet("hello", test.HelloServlet.class);

Depending on what you're developing, there are two hooks where you can run this code.

1. If you're developing a publicly reusable modular web fragment JAR file such as existing frameworks like JSF and Spring MVC, then use a ServletContainerInitializer .

    public class YourFrameworkInitializer implements ServletContainerInitializer { @Override public void onStartup(Set<Class<?>> c, ServletContext servletContext) throws ServletException { servletContext.addServlet("hello", test.HelloServlet.class); } } 

2. Or, if you're using it as an internally integrated part of your WAR application, then use a ServletContextListener .

    @WebListener public class YourFrameworkInitializer implements ServletContextListener { @Override public void contextInitialized(ServletContextEvent event) { event.getServletContext().addServlet("hello", test.HelloServlet.class); } // ... } 

You only need to make sure that your web.xml is compatible with Servlet 3.0 or newer (and thus not Servlet 2.5 or older), otherwise the servletcontainer will run in fallback modus complying the declared version and you will lose all Servlet 3.0 features.

<?xml version="1.0" encoding="UTF-8"?>
<web-app 
    xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    version="3.0"
>
    <!-- Config here -->
</web-app>

See also:

• ServletContainerInitializer vs ServletContextListener
• @WebServlet annotation with Tomcat 7
• Design Patterns web based applications
• Splitting up shared code and web.xml from WAR project to common JAR project

Answer 3

如果您使用的是tomcat 7或更高版本，则可以通过注释完成此操作

@WebServlet("/hello")