get filename from a stacktrace

Question

I have a failing unit test and i am writing a custom jasmine reporter that would requires me to get the name of the file from the stack trace provided by it.

Verify the most recent consumer review is showing all information. (0.683 sec) - Expected true to be false, 'test title'. at Object.<anonymous> (/Users/xyz/Documents/tests/somefolder/xyz.test.js:25:72) at /Users/xyz/Documents/node_modules/jasminewd2/index.js:96:23 at new Promise (/Users/xyz/Documentsc/node_modules/selenium-webdriver/lib/promise.js:1043:7.....

What is the best way just to get the name of the file xyz.test.js from above?

Answer 1

If the traceback is stored in a string, and you want to extract the filename using regex (may not work for all types of exceptions):

 var traceback = "Verify the most recent consumer review is showing all information. (0.683 sec) \\ - Expected true to be false, 'test title'. \\ at Object.<anonymous> (/Users/xyz/Documents/tests/somefolder/xyz.test.js:25:72) \\ at /Users/xyz/Documents/node_modules/jasminewd2/index.js:96:23 \\ at new Promise (/Users/xyz/Documentsc/node_modules/selenium-webdriver/lib/promise.js:1043:7....." console.log(/\\(.*\\/([^\\/]*.js).*\\)/.exec(traceback)[1]) 

\(.*/([^/]*.js).*\)

Debuggex Demo

Answer 2

You could probably use a regexp for this, but if you want a bit more functionality, stacktrace-parser is useful:

const parse = require('stacktrace-parser').parse;
const path  = require('path');

let trace = `
        - Expected true to be false, 'test title'.
            at Object.<anonymous> (/Users/xyz/Documents/tests/somefolder/xyz.test.js:25:72)
            at /Users/xyz/Documents/node_modules/jasminewd2/index.js:96:23
            at new Promise (/Users/xyz/Documentsc/node_modules/selenium-webdriver/lib/promise.js:1043:7
`;

console.log( path.basename( parse(trace)[0].file ) )
// outputs: xyz.test.js