How to read only alphabetical characters from a txt file while ignoring white spaces and other special characters?

Question

I use pointers to open a .txt file that consists of several paragraphs. I used a for loop to store the .txt file into a char word[i] array and then printf it.

Everything worked well except I don't want to store white spaces and special characters. I only want to store alphabetical characters such as ABCD......Z into my char word[i] array.

I know I have to put if functions into my for loops, but I don't know the exact syntax. Please help.

here is the for loop of my code :

 for (i=0; i<1730; i++ )
   {
       fscanf(fptr,"%c", &word[i]);
       printf("%c", word[i]);
   };

Answer 1

#include <stdio.h>
#include <string.h>
int main() 
{
    FILE *fptr;
    char chr;
    char *file_name="IdentifiedParts.txt";
    fptr = fopen(file_name, "r");
    while ( (fscanf(fptr,"%c",&chr)) != EOF ) {
           //ASCII values : 65-90 => A-Z ,  97-122 => a-z
        if( (chr >= 97 && chr <= 122 ) || (chr >= 65 && chr <= 90 ) ) {
             printf("%c", chr);
        }
    }
    fclose(fptr);
    return 0;
}

      OR 

   while ( (fscanf(fptr,"%c",&chr)) != EOF ) {
          if(isalpha(chr)) {
            printf("%c", chr);
          }
    }

Answer 2

something like this:

#include <stdio.h>
#include <ctype.h>

int main(void){
    char word[1730];
    FILE* fptr = fopen("input.c", "r");
    int i, ch;

    for (i = 0; i<1730 && (ch = fgetc(fptr)) != EOF; i++ ){
        if(isalpha(ch))
            printf("%c", word[i]=ch);
    }
    fclose(fptr);
    return 0;
}

---

#include <stdio.h>

int main(void){
    char word[1730];
    FILE* fptr = fopen("input.txt", "r");

    while(!feof(fptr)){
        while(1 == fscanf(fptr, "%1729[A-Za-z]", word)){
            printf("%s", word);
        }
        fscanf(fptr, "%*[^A-Za-z]");
    }

    fclose(fptr);
    return 0;
}