How to print special characters in a loop?

Question

I'm trying to print the following pattern:

@@@@@@@@
@@@@@@@
@@@@@@
@@@@@

However, I am getting this instead:

@ABCDEFG
ABCDEFG
BCDEFG
CDEFG

I'm not sure what I am doing wrong. I would appreciate any feedback or direction.

#include <stdio.h>
#define ROWS 4
#define CHARS 8

int main(void)
{
    for(int row = 0; row < ROWS; row++)
    {
        for(char ch = ('@' + row); ch < ('@' + CHARS); ch++)
            printf("%c", ch);
        printf("\n");
    }

    return 0;
}

Answer 1

The + operator doesn't work the way you think it does. @ is converted to it's ASCII value (64) then you add row . When row is 2 , you are saying: print the character that coresponds the number (64 + 2) which is A .

Here's an ASCII Table

I would change the inside loop to something like this:

for(int ch = row; ch < CHARS; ch++) {
    printf("%c", '@');
}
printf("\n");

Answer 2

Why are you complicating second for with that character. It can be simply

for(int col = row; col < CHARS; col++)
    printf("%c", '@');

Answer 3

将 ch 更改为 '@' printf("%c", '@');