php html Why isn't my form showing on the webpage?
Question
I simply cannot understand how and why I am not seeing a form, when opening my site??? I wan a form consisting of bot username, password and a subit box to appear, though I don't see the solution here...
A solution and explaining would be much appreciated.
<?php
error_reporting(E_ALL ^ E_NOTICE);
session_start();
?>
<!DOCTYPE html>
<!--
-->
<html>
<head>
<meta charset="UTF-8">
<title>World Talk Login</title>
</head>
<body>
<?php
$form = "<form action='./login.php' method='post'>
<table>
<tr>
<td>Username:</td>
<td><input type='text' name='user'/></td>
</tr>
<tr>
<td>Password:</td>
<td><input type='password' name='password'/></td>
</tr>
<tr>
<td></td>
<td><input type='submit' name='loginbtn' value='Login'/></td>
</tr>
</table>
</form>";
if ($_POST['loginbtn']){
$user = $_POST ['user'];
$password = $_POST['password'];
if ($user) {
if ($password){
echo "$user - $password <hr /> $form";
}
else
echo "You must enter your password. $form";
}
else
echo "You must enter your username. $form";
}
?>
</body>
</html>
thanks in advance!
4 answers
solution1
0 2016-10-09 20:02:01
You didn't print your form from PHP or mistakenly wrapped your form in PHP. It was wrapped around the <?php tag in the variable $form but no print to screen.
This is how it should look like below with errors working correctly ;-)
<?php
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
session_start();
?>
<!DOCTYPE html>
<!--
-->
<html>
<head>
<meta charset="UTF-8">
<title>World Talk Login</title>
</head>
<body>
<form action='./login.php' method='post'>
<table>
<tr>
<td>Username:</td>
<td><input type='text' name='user'/></td>
</tr>
<tr>
<td>Password:</td>
<td><input type='password' name='password'/></td>
</tr>
<tr>
<td></td>
<td><input type='submit' name='loginbtn' value='Login'/></td>
</tr>
</table>
</form>
<?php
if ($_POST['loginbtn']){
$user = $_POST ['user'];
$password = $_POST['password'];
if ($user) {
if ($password){
echo "$user - $password <hr /> $form";
}
else
echo "You must enter your password. $form";
}
else
echo "You must enter your username. $form";
}
?>
</body>
</html>
solution2
0 2016-10-09 20:04:47
您也没有回显您的变量
solution3
0 ACCPTED 2016-10-09 20:05:00
Try changing your php at the bottom to the following.
if ($_POST['loginbtn']){
$user = $_POST ['user'];
$password = $_POST['password'];
if($user != "" && $password != "") {
echo "$user - $password <hr /> $form";
}
if($user == "") {
$error .= "You must enter your username.</br>";
}
if($password == "") {
$error .= "You must enter your password.";
}
if($error != "") {
echo $error.$form;
}
} else {
echo $form;
}
solution4
0 2016-10-09 20:07:34
<html>
<head>
<meta charset="UTF-8">
<title>World Talk Login</title>
</head>
<body>
<?php
$form = "<form action='./login.php' method='post'>
<table>
<tr>
<td>Username:</td>
<td><input type='text' name='user'/></td>
</tr>
<tr>
<td>Password:</td>
<td><input type='password' name='password'/></td>
</tr>
<tr>
<td></td>
<td><input type='submit' name='loginbtn' value='Login'/></td>
</tr>
</table>
</form>";
echo $form;
if (!isset($_POST['loginbtn'])){
$user = (!isset($_POST['user']));
$password = (!isset($_POST['password']));
}
else{
}
?>
</body>
</html>
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