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passing text variable using shell_exec

I try to passing text using shell_exec.

$message="I go to school";

shell_exec("nohup php -q sendmail.php $picture $message");

but I get only the one word of message when I user argv[2]. what the problem?

您必须为文本添加“

shell_exec("nohup php -q sendmail.php $picture \"$message\"");

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