Invalid Syntax error python 3.5.2

Question

I'm getting syntax error in this particular line.

print "Sense %i:" %(i),

Full code:

for i in range(len(meas)):
    p = sense(p, meas[i])
    r = [format(j,'.3f') for j in p]
    print "Sense %i:" % (i),
    print r,
    entropy(p)
    p = move(p, mov[i])
    r = [format(j,'.3f') for j in p]
    print "Move %i:" % (i),
    print r,
    entropy(p)
    print

Answer 1

Several things:

• In Python 3, print is a function, no more a statement like it was with Python 2. So, you need to add parenthesis to call the function,
• the % operator used for string formatting is deprecated. With Python 3, you should use the format method (or the format function),
• the % operator usually take a tuple as a second parameter: the expression "(i)" is not a tuple but a constant. With Python, the singleton tuple has a trailing comma like this: "(i,)".
• use the keyword argument end="" to replace the newline by an empty string (but I'm not sure this is what you want)

So, you can replace your code by:

print("Sense {}:".format(i), end="")

EDIT: add code from comment

Your code should be converted in Python 3 like bellow:

for i in range(len(meas)):
    p = sense(p, meas[i])
    r = [format(j,'.3f') for j in p]
    print("Sense {0}:".format(i), end="")
    print(r, end="")
    entropy(p)
    p = move(p, mov[i])
    r = [format(j,'.3f') for j in p]
    print("Move {0}:".format(i), end="")
    print(r, end="")
    entropy(p)
    print()

Answer 2

Try this:

print ("Sense %s:" %i)

Will work just fine

Answer 3

在python 3中，print是一个函数，您必须使用方括号： print("Sense %i:" %(i))