I'm try to build a snack machine where you can choose your snack, get the price and then click the button to pay.
Like: The price is 0,60 € 0.05(button) 0.10(button) .... if you press 0.05-button the price will reduce to 0,55€
Why don't I get a "test" echo after I click the button?
Here is my code
<?php
if(isset($_GET['mars']))
{
$mars = "0,60";
echo "Bitte Zahlen Sie noch <input type=\"button\" value=\"$mars\"> Euro<br>";
echo "<input type=\"submit\" value=\"0,05\" name=\"fcent\">";
if(isset($_GET['fcent']))
{
echo "test";
}
}
?>
First, there appears to be no form-tag in your code. Without a form tag, it would be a miracle that pressing that button actually submits it via PHP. In other words, you need to wrap your form elements in a
<form></form>
Tag.
Secondly, the nestedif
:if(isset($_GET['fcent']))
is unreachable because when you press thefcent
button; the$_GET['mars']
is no more in scope and since your code explicitly demands to be run when$_GET['mars']
is SET, nothing would happen. The Snippet below takes this 2 Points into account and you can fine-tune it even further to meet your needs...
NOTE: You have to be sure that your URL reads something similar to this:http://localhost/index.php?mars=some-value
<?php
$mars = "0,60";
$payForm = "<form name='whatever' method='get' action=''><br>";
$payForm .= "Bitte Zahlen Sie noch <input type=\"button\" value=\"$mars\"> Euro<br>";
$payForm .= "<input type=\"submit\" value=\"0,05\" name=\"fcent\">";
$payForm .="</form>";
if(isset($_GET['mars'])){
echo $payForm;
}
if(isset($_GET['fcent'])){
echo $payForm;
echo "test";
}
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