Form does not submit with php echo
Question
I have the following code:
index.php
<?php
if (isset($_POST['post'])) {
echo "<script>alert(".$_POST['val1'].")</script>";
}
?>
<html>
...
<body>
...
<?php
echo "<form id='form_id' method='post' name='myform'>";
echo "<input id='val1' type='text' value='7'>";
echo "<input id='submit' type='submit' value='submit'>";
echo "</form>";
?>
...
<body>
</html>
This will create a form, a text field and a submit button. All those shown perfectly fine except it would not submit the form. So my question is why does my form not work here and what should I do to solve this problem without moving it out from php.
2 answers
solution1
0 ACCPTED 2017-08-13 15:04:43
Problem is that you are missing name attributes for the elements:
<?php
if (isset($_POST['post'])) {
echo "<script>alert(".$_POST['val1'].")</script>";
}
?>
<html>
...
<body>
...
<?php
echo "<form id='form_id' method='post' name='myform'>";
echo "<input id='val1' name='val1' type='text' value='7'>";
echo "<input id='submit' name='post' type='submit' value='submit'>";
echo "</form>";
?>
...
<body>
</html>
You can notice the addition of name attribute for text field and submit button. Only name attribute will be used to identify the fields when form gets posted.
solution2
0
In addition to Thamilan's answer about the name attribute you should use empty ($POST['val1']) instead of isset . Here is a complete working example:
<!DOCTYPE html>
<head>
<?php
if (empty($_POST['val1']))
print "<title>Not yet submitted</title>";
else
{
echo "<script>alert(".$_POST['val1'].")</script>";
echo "<title>Submitted</title>";
}
?>
</head>
<body>
<?php
echo "<form id='form_id' method='post' name='myform'>";
echo "<input name='val1' id='val1' type='text' value='7'>";
echo "<input id='submit' type='submit' value='submit'>";
echo "</form>";
?>
</body>
</html>
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