search using a keyword and display all names that have that keyword in a table php
Question
<HTML>
<?php
include 'dbconfig.php';
$hotelname=$_GET['Hotel'];
$con = mysqli_connect($dbhostname, $dbusername, $dbpassword, $dbname)
or die("<br>Cannot connect to database!\n");
$query = "SELECT * FROM Hotel WHERE hotelname LIKE '%".$hotelname."%'";
$result = mysqli_query($con, $query);
if($result) {
echo "Brodley, Matt";
echo "<b> </b>";
echo "You are searching keywords: xxxx";
echo "<TABLE BORDER=1>";
echo "<tr><TD>hotelname<TD>city\n";
while($row = mysqli_fetch_array($result)){
$hotelname= $row['hotelname'];
$city= $row['city'];
echo "<tr><TD>$hotelname<TD>$city\n";
}
echo "</TABLE>";
}else echo "no hotel found for search keyword xxxx";
mysqli_free_result($result);
mysqli_close($con);
?>
</HTML>
So once I enter into the searched_word textbox on the previous page it should display a list of hotelnames that match the searched_word. Say when I search Omni it takes the searched_word but just displays
no hotel found for search keyword Omni
In my table that its database their is a hotelname that matches the searched_word
2 answers
solution1
0 2016-10-19 04:15:29
you may try replacing
if($result == searched_word){
by
if($result){ // if(mysqli_num_rows($result) > 0)
solution2
0 2016-10-19 04:45:00
You can try the below code. Here I have added the statement to print the mysql query error and also removed "street" column in sub query.
<HTML>
<?php
include 'dbconfig.php';
$con = mysqli_connect($dbhostname, $dbusername, $dbpassword, $dbname)
or die("<br>Cannot connect to database!\n");
$query = "SELECT hotelname,city FROM Hotel WHERE city IN ( SELECT city FROM Branch WHERE hotelname LIKE '$_GET[searched_word]')";
$result = mysqli_query($con, $query);
if($result){
echo "Brodley, Matt";
echo "You are searching keywords: $_GET[searched_word]";
echo "<TABLE BORDER=1>";
echo "<tr><TD>hotelname<TD>city\n";
while($row = mysqli_fetch_array($result)){
$hotelname= $row['hotelname'];
$city= $row['city'];
echo "<tr><TD>$hotelname<TD>$city\n";
}
echo "</TABLE>";
}
else {
echo "no hotel found for search keyword $_GET[searched_word]";
printf("Errormessage: %s\n", mysqli_error($con));
}
mysqli_free_result($result);
mysqli_close($con);
?>
</HTML>
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