This function is supposed to catch exceptions in the main execution. If there is an exception it should print out the error with log.error(traceback.print_exc())
and clean up with exit_main()
.
def main():
try:
exec_app()
except KeyboardInterrupt:
log.error('Error: Backup aborted by user.')
exit_main()
except Exception:
log.error('Error: An Exception was thrown.')
log.error("-" * 60)
log.error(traceback.print_exc())
log.error("-" * 60)
exit_main()
Unfortunately log.error(traceback.print_exc())
does only return None
if there is an exception. How can I make traceback print the full error report in this case?
PS: I use python 3.4.
From its __doc__
:
Shorthand for 'print_exception(sys.exc_type, sys.exc_value, sys.exc_traceback, limit, file)'
That is, it isn't supposed to return anything, its job is to print. If you want the traceback as a string to be logged, use traceback.format_exc()
instead.
I usually use traceback.print_exc()
just for debugging. In your case, to log your exception you can simply do the following:
try:
# Your code that might raise exceptions
except SomeSpecificException as e:
# Do something (log the exception, rollback, etc)
except Exception as e:
log.error(e) # or log(e.message) if you want to log only the message and not all the error stack
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