Shell script: grep a table of values from a file

Question

I have a result file that looks like this:

data data data data data...
data data data data data...
data data data data data...

#0
data data is 2

#1
data data is 2

testing data (  )

   n         m  
  256      729.44      
  352     1555.07      
  448     2649.68      

#2
data data is 2

#3
data data is 2

I need to grep only the table that will always have 2 columns of n and m(it can get very long). So the output should be:

    n         m  
  256      729.44      
  352     1555.07      
  448     2649.68

I've tried using awk and grep but I can only get one line not the whole table. Any help would be appreciated it.

Answer 1

Assuming there is no empty lines in the table, then one can use gawk like this:

awk '$1 == "n" && $2 == "m"' RS=

It will print the block which start with n , and m in the two first fields.

Answer 2

使用AWK，您将打印“字段数”等于2的所有行：

awk 'NF == 2' data.txt