PHP - Break out of an if statement

Question

So I have this code which assigns different variables depending on if a file exists or not:

$progress_file_path = './data/progress.txt';

if (file_exists($progress_file_path) && count($scanned) > 0) {
    $scanned = file($progress_file_path);
    $last = end($scanned);
    $end = $limit + count($scanned);
}
else { 
    $last = 'unset'; 
    $end = $limit;
}

but I need to do more with this, I need to make sure the file has content in it. I do the check in the conditional like this:

if (file_exists($progress_file_path) && count(file($scanned)) > 0)

because the $scanned variable hasn't been defined yet. So the ideal solution would be if I can break out of the if statement, and jump to the else part of the conditional.

Something like this:

$progress_file_path = './data/progress.txt';

if (file_exists($progress_file_path)) {
    $scanned = file($progress_file_path);

    if (count($scanned) > 0) { break; }

    $last = end($scanned);
    $end = $limit + count($scanned);

}I 
else { 
    $last = 'unset'; 
    $end = $limit;
}

but that doesn't work, you can't break or continue out of an if statement. I was thinking maybe using goto to jump into the else part of the conditional but I doubt that will work either. Is there a way to jump to the else part of a conditional like this?

Answer 1

You can try to check both of your conditions in one if statement to have at least one else like this

$progress_file_path = './data/progress.txt';

if (file_exists($progress_file_path) && count(file($progress_file_path)) > 0) {
    $scanned = file($progress_file_path);

    $last = end($scanned);
    $end = $limit + count($scanned);
} else {
    $last = 'unset'; 
    $end = $limit;
}

Answer 2

Refining Anant answer

$progress_file_path = './data/progress.txt';
$last = 'unset'; 
$end = $limit;
if (file_exists($progress_file_path)) {
    $scanned = file($progress_file_path);
    if (count($scanned) < 0) { 
        $last = end($scanned);
        $end = $limit + count($scanned);
    }
}