I have a big .csv file (~600k lines, 56Mo), and inside there is database lines (on each line, there's an id, a client name, a client address, a client birthday date, etc). The problem is that, on some lines, some data is written badly (commas not supposed to be there, that mess up the columns).
I guessed that I had to do some RegEx to detect the problematic lines, and to replace the wrong commas with a dash or anything. I followed this article , and, after some tries, I got him to detect the messed-up lines.
Private Sub simpleRegex()
Dim strPattern As String: strPattern = "[^a-zA-Z0-9_,\-]([A-z]+)\,[^a-zA-Z0-9_,\-]([A-z]+)"
Dim strReplace As String: strReplace = "[^a-zA-Z0-9_,\-][A-z]+\-[^a-zA-Z0-9_,\-][A-z]"
Dim regEx As Object
Set regEx = CreateObject("VBScript.RegExp")
Dim strInput As String
Dim Myrange As Range
Set Myrange = ActiveSheet.Range("A1:A2000")
For Each cell In Myrange
If strPattern <> "" Then
strInput = cell.Value
With regEx
.Global = True
.MultiLine = True
.IgnoreCase = False
.Pattern = strPattern
End With
If regEx.Test(strInput) Then
MsgBox (regEx.Replace(strInput, strReplace))
Else
End If
End If
Next End Sub
The problem is, this solution works if I wanted to change the cibled lines with an unique value, a predefined string (like strReplace="replacement words"). What I want, is to be able to target a succession of characters that match my pattern, and to replace only one character (the comma) in it. An example of it would be :
728,"HAY,HAYE",Marie,François,RAUTUREAU,85,29/05/1856,68;
into :
728,"HAY-HAYE",Marie,François,RAUTUREAU,85,29/05/1856,68;
Do you have a solution?
(Sorry if bad english, it's not my mother tongue).
You can use (?<=(Your Word))
to catch specific characters after a specific word. In your case, this code will help you find the comma:
(?<=(HAY))\,
Update:
Try this and I also updated the demo:
,(?=[^"]+")
The correct approach here (since you commented that double quotes only appear as field delimiters) is to match double quoted substrings with a simple "[^"]+"
regex and replace commas with hyphens only inside the matches .
Here is a sample code:
Sub CallbackTest()
Dim rxStr As RegExp
Dim s As String
Dim m As Object
s = """SOME,MORE,HERE"",728,""HAY,HAYE"",Marie,François,RAUTUREAU,85,29/05/1856,68;"
Set rxStr = New RegExp
rxStr.pattern = """[^""]+"""
rxStr.Global = True
For Each m In rxStr.Execute(s)
s = Left(s, m.FirstIndex) & Replace(m.Value, ",", "-") & Mid(s, m.FirstIndex + Len(m.Value) + 1)
Next m
Debug.Print s ' Print demo results
' => "SOME-MORE-HERE",728,"HAY-HAYE",Marie,François,RAUTUREAU,85,29/05/1856,68;
End Sub
If I got you correct, then there is no need for Regex
at all.
With a simple Split
you can do it too.
Private Sub simpleReplace()
Dim str() As String, cell As Variant, Myrange As Range, i As Long
Set Myrange = ActiveSheet.Range("A1:A2000")
For Each cell In Myrange
str = Split(cell.Value, """")
If UBound(str) Then
For i = 1 To UBound(str) Step 2
str(i) = Replace(str(i), ",", "-")
Next
cell.Value = Join(str, """")
End If
Next
End Sub
this will split your 728,"HAY,HAYE",Marie,François,RAUTUREAU,85,29/05/1856,68;
into:
(0) 728,
(1) HAY,HAYE
(2) ,Marie,François,RAUTUREAU,85,29/05/1856,68;
Now every second part of the Split
(odd numbers) will be normally enclosed in "
. So all that is left, is to Replace
the commas there and push it into the cell again.
And if there is no "
found, then it will skip this line (because the upper bound is 0)
If you still have any Questions or if that is not what you are looking for, pls tell :)
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