JQuery issue "TypeError: $.getJSON is not a function"
Question
I've got this piece of code:
$(document).ready(function () {
$.getJSON('http://localhost:5000/', function (response) {
console.log(response);
});
});
localhost:5000 is a flask/python script that returns a json like:
{
"data": [
0,
0,
0,
And I'm getting:
$.getJSON is not a function TypeError: $.getJSON is not a function
Any tips where I can start untangling the whoolball?
Thanks!
Edit:
HTML:
<!DOCTYPE html>
<html>
<head>
<script src="https://code.jquery.com/jquery-3.1.1.slim.min.js"></script>
<script src="lib/main.js"></script>
</head>
<body>
</body>
</html>
lib/main.js is where the document.ready is located.
Thanks!
6 answers
solution1
170 ACCPTED 2016-11-15 02:06:19
You seem to be using slim version of jquery which does not have the method getJSON thats why you are getting this error.
Please use the full version of jquery instead from the below link.
https://code.jquery.com/jquery-3.1.1.min.js
Slim version of jquery excludes ajax , animations effects etc
solution2
3 2017-12-15 22:12:34
Thus happens commonly when migrating codebases from jQuery v1.x+ to v3.0+ as jQuery updated/deprecated/discontinued some of it's API.
I recommend using jQuery Migrate which will address this, along with other issues:
Get it here via CDN:
https://cdnjs.com/libraries/jquery-migrate
If using Gulp/Grunt, you can import into your project using
npm install --save jquery jquery-migrate
Github Repository - https://github.com/jquery/jquery-migrate
Read more about jQuery v3.0+.. http://blog.jquery.com/2016/06/09/jquery-3-0-final-released/
solution3
1 2018-01-26 15:27:41
function cinta(){
$.getJSON('http://localhost:5000/', function (response) {
console.log(response);
});
}
cinta();
$(document).ready(function () {
console.log('yesss');
});
This work for me in python flask
solution4
0 2020-12-21 13:18:10
You can also use Fetch with async and await :
async function getData(){
const response = await fetch( "http://localhost:5000/"
);
return response.json();
}
getData().then((data) => {
//... your code
})
solution5
0 2022-04-24 00:20:09
I had the same error with my piece of code,
$.getJson("/foo.json")
The issue was that my function is actually spelled
$.getJSON
NOT $.getJson .
solution6
0 2022-07-16 21:05:48
Please use the full version of jquery CDN instead Slim/lite version.
<script src="https://code.jquery.com/jquery-3.1.1.min.js"></script>
without cross-origin and integrity, I hope it will work
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.