I have a one-dimensional numpy array with numbers, and I want each number replaced with the index of the quantile it belongs to.
This is my code for quintile indices:
import numpy as np
def get_quintile_indices( a ):
result = np.ones( a.shape[ 0 ] ) * 4
quintiles = [
np.percentile( a, 20 ),
np.percentile( a, 40 ),
np.percentile( a, 60 ),
np.percentile( a, 80 )
]
for q in quintiles:
result -= np.less_equal( a, q ) * 1
return result
a = np.array( [ 58, 54, 98, 76, 35, 13, 62, 18, 62, 97, 44, 43 ] )
print get_quintile_indices( a )
Output:
[ 2. 2. 4. 4. 0. 0. 3. 0. 3. 4. 1. 1.]
You see I start with an array initialized with the highest possible index and for every quintile cutpoint substract 1 from each entry that is less or equal than the quintile cutpoint. Is there a better way to do this? A build-in function that can be used to map numbers against a list of cutpoints?
First off, we can generate those quintiles
in one go -
quintiles = np.percentile( a, [20,40,60,80] )
For the final step to get the offsets, we can simply use np.searchsorted
and this might be the built-in you were looking for, like so -
out = np.searchsorted(quintiles, a)
Alternatively, a direct translation of your loopy code to a vectorized version would be with broadcasting
, like so -
# Use broadcasting to perform those comparisons in one go.
# Then, simply sum along the first axis and subtract from 4.
out = 4 - (quintiles[:,None] >= a).sum(0)
If quintiles
is a list, we need to assign it as an array and then use broadcasting
, like so -
out = 4 - (np.asarray(quintiles)[:,None] >= a).sum(0)
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