I am Developing a Real Time Application.I am Created a ASP.NET MVC Client Application and WCF Service.and Again i need to add the signalR concept in WCF and Client side for real time notification.
For this i am created an self hosted signalR and added this solution to WCF Service Solution in visual Studio.
My WCF Service Running URL Address is : http://localhost:63694/Service1.svc
My Requirement is WCF and SignalR work together.and the CLient is ASp.Net MVC4
The WCF and ASP.NET MVC codes are here
SignalR code:-
namespace SelfHostingSignalR
{
class Program
{
static void Main(string[] args)
{
try
{
string url = "http://localhost:63694/Signalr";
using (WebApp.Start(url))
{
Console.WriteLine("Server running on {0}", url);
Console.ReadLine();
}
}
catch (Exception e)
{
Console.WriteLine(e.Message);
Console.ReadLine();
}
}
}
class Startup
{
public void Configuration(IAppBuilder app)
{
app.UseCors(CorsOptions.AllowAll);
app.MapSignalR();
}
}
public class MyHub : Hub
{
public void Send(string user)
{
Clients.All.addMessage(user);
}
}
}
For signalr url i am hardcoded some value with wcf url address:
string url = " http://localhost:63694/Signalr ";
i don't know is it correct or not.Could anyone provide me a solution to solve this?
how do i configure the WCF Service Running Url to signalR url?
To self-host SignalR on a WCF web service application, you just need to configure /signalr
in Startup.cs
:
public class Startup
{
public void Configuration(IAppBuilder app)
{
app.UseCors(CorsOptions.AllowAll);
app.MapSignalR();
}
}
with MyHub defined like this:
public class MyHub : Hub
{
public void Send(string user)
{
Clients.All.addMessage(user);
}
}
in your client MVC .NET application, you can invoke server method and define client method as below:
[HttpGet]
public async Task<ActionResult> SignalR()
{
dynamic model = new ExpandoObject();
using(var hubConnection = new HubConnection("http://localhost:63694"))
{
var myHub = hubConnection.CreateHubProxy("MyHub");
myHub.On<string>("addMessage", (user) =>
{
model.User = user;
});
await hubConnection.Start();
await myHub.Invoke("Send", "an user");
}
return View(model);
}
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