I have virtual method that calls static method of appropriate class:
class A{
public:
static void bar() {std::cout<<"bar A\n";}
virtual void foo(){
//Some A work...
bar();
}
};
class B : public A{
public:
static void bar() {std::cout<<"bar B\n";}
virtual void foo() override {
//Some B work...
bar(); //prints bar B, as intended.
}
};
But now I want to have class C, with method foo(), with the only difference of calling C::bar() in the end:
class C : public A {
public:
static void bar() override {std::cout<<"bar C\n";}
virtual void foo(){
//Some **A** work...
bar(); //I want to print "bar C" here
}
}
However, here I needed to make full copy of method A::foo definition. I could also introduce dummy virtual method like `virtual void callStaticBar(){bar();} and override it in class C with the same text. Is there more elegant way to do such a thing?
No. If C::foo()
is not defined, calling foo()
on a C
instance will really call A::foo()
; since class A
has no knowing of class C
(except is those cases with the vtable), there is no way for A::foo()
to call C::bar()
, regardless of the fact that the original call came from a C
instance.
You need to use your method of dummy virtual method or to tell us more about what you want to achieve, as they might be a better solution in a particular situation.
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