我需要将简单的handle_call函数“注入”我的一个依赖项,是否可以在不修改原始依赖项的情况下完成?
I don't think that's possible without modifying it's source. (depends on dep though) I had such problem on hackathon once. I've just forked it's source on github, modified it and replaced the import with git one like that:
{ :foobar, git: "https://github.com/elixir-lang/foobar.git" }
It's a hack, but it works. Please give us more concrete example maybe we can do it another way.
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