I've been trying to delete a node from a BST. I'm taking help of two functions where one (findInorderSuccesor) is being called when a node has two Children. Problem is, the node that comes in as a replacement for the deleted node, is not getting deleted from it's original position. As a result, I've two nodes with the same value.
obj.addNode(8);
obj.addNode(2);
obj.addNode(5);
obj.addNode(1);
obj.addNode(13);
obj.addNode(10);
obj.addNode(15);
obj.deleteNode(obj.root,8);
public void deleteNode(treeNode focusNode, int data)
{
if(data<focusNode.data)
deleteNode(focusNode.left,data);
else if (data>focusNode.data)
deleteNode(focusNode.right,data);
else
{
if(focusNode.right == null && focusNode.left == null)
focusNode=null;
else if(focusNode.left!=null && focusNode.right==null)
focusNode = focusNode.left;
else if (focusNode.right!=null && focusNode.left==null)
focusNode = focusNode.right;
else
{
//node has two children
BSTDeletion obj = new BSTDeletion();
treeNode replacement =obj.findInorderSuccessor(focusNode.right);
focusNode.data = replacement.data;
deleteNode(focusNode.right, replacement.data);
}
}
}
public treeNode findInorderSuccessor(treeNode focusNode)
{
treeNode preFocusNode = null;
while(focusNode!=null)
{
preFocusNode = focusNode;
focusNode = focusNode.left;
}
return preFocusNode;
}
As Boola wrote, You need to know the parent of the node You are deleting.
When you say focusNode = null; you only make the reference null, you don't remove the object from the tree, because the parent is still referencing that node. You need something like this:
public void deleteNode(treeNode focusNode, int data)
{
if(data<focusNode.data)
deleteNode(focusNode.left,data);
else if (data>focusNode.data)
deleteNode(focusNode.right,data);
else
{
treeNode parent = focusNode.getParent(); // get the parent.
if(focusNode.left==null && focusNode.right==null)
{
if(parent.left.equals(focusNode))
parent.left = null; //Set the parents reference to null.
else
parent.Right = null;
}
else if(focusNode.left!=null && focusNode.right==null)
{
if(parent.left.equals(focusNode))
parent.left = focusNode.left; //Reassign the parents reference to the correct node.
else
parent.right = focusNode.left;
}
and so on.
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