Yii generate model without Gii

Question

I need to generate a model file without the use of Gii. Are there any command Yii?

$table = "myTable";
Yii::app()->generateModel($table); // ?

Answer 1

Don't think there is a command. You could create the model, or the command, yourself. Other option would be to make the requests to Gii via curl.

Answer 2

Perhaps is officially deprecated, you can generate code with Yii Command Line Tools

I have tested it with Yii 1.1.17.

First you need to create a new file on protected/commands called for example NewmodelCommand.php to create a new yii command . We need to avoid to use shell interactive tool and call command directly from our code in controllers, models, etc. To get it, we inherit Yii core class ModelCommand . This class originally force person to type on interactive shell.

<?php

Yii::import('system.cli.commands.shell.ModelCommand');


class NewmodelCommand extends ModelCommand
{

}

That is all. You can test command from CLI into your operating system. In Linux, open your terminal and go to /protected/ directory and type:

./yiic

You will see something like this:

...
The following commands are available:
 - message
 - migrate
 - newmodel
 - shell
 - webapp
...

Play a little with it. Type again:

./yiic newmodel

And you will see all command help and documentation.

To generate a model with this command you need at least model_name as first parameter. Command will use same model name as database table name:

./yiic newmodel MyNewModel

If you have different model and database name:

./yiic newmodel MyNewModel tbl_new_model

If you have troubles using yiic, locating/connecting your db, etc, make sure to setup properly your console environment on protected/config/console.php and check all official docs about Yii console applications .

Finally in your code you can use your command as you want:

$path = '/full/path/to/protected';
$new_model_name = 'MyNewModel';
shell_exec( $path . "/./yiic newmodel $new_model_name" );