<pre class="article">
aaa aaa aaabbb
</pre>
(function ($) {
var test = $("pre.article");
test.html(test.text().replace(/aaa/g, '<span class="aaa">111</span>'));
});
})(jQuery)
how to keep the results into: 111 111 aaabbb
please help me ....
You can add a \\s to the end of the search text to only look for that pattern with any white space character after the pattern.
.replace(/aaa\\s/g, '<span class="aaa">111</span>')
To keep the space without having to add it back in use \\b, which anchors to the end of a word.
.replace(/aaa\\b/g, '<span class="aaa">111</span>')
You can try different expressions on a string with a regex tester like regex101
Just make sure you catch also the space after the aaa
:
$(function() { var test = $("pre.article"); test.html(test.text() .replace(/aaa /g, '<span class="aaa">111</span> ')); })
.aaa{color:red}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <pre class="article"> aaa aaa aaabbb </pre>
(and inside the replacement - add that space back)
JavaScript的第5行中,您要在替换的aaa和跨度的111之间留一个空格:
.replace(/aaa /g, '<span class="aaa">111 </span>'));
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