ajax submit form why it cannot echo $_POST
Question
I'm test using ajax submit form (submit to myself page "new1.php")
The thing that I want is, after click submit button, it will echo firstname and lastname. But I don't know why I do not see the firstname and lastname after submit.
here is new1.php page
<?php
echo $_POST['firstname']."<br>";
echo $_POST['lastname']."<br>";
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Document</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
</head>
<body>
<form id="myform" action="new1.php" method="post">
Firstname : <input type="text" name="firstname"> <br>
Lastname : <input type="text" name="lastname"> <br>
<input type="submit" value="Submit">
</form>
<script>
// this is the id of the form
$("#myform").submit(function(e) {
$.ajax({
type: "POST",
url: 'new1.php',
data: $("#myform").serialize(), // serializes the form's elements.
success: function(data)
{
alert('yeah'); // show response from the php script.
}
});
e.preventDefault(); // avoid to execute the actual submit of the form.
});
</script>
</body>
</html>
5 answers
solution1
3 ACCPTED 2017-01-11 11:50:54
In your case the best option to retrieve values as JSON format using json_encode in your PHP code and then accessing these values through data object.
Example:
PHP code:
if($_POST)
{
$result['firstname'] = $_POST['firstname'];
$result['lastname'] = $_POST['lastname'];
echo json_encode($result);
die(); // Use die here to stop processing the code further
}
JS code:
$("#myform").submit(function (e) {
$.ajax({
type : "POST",
url : 'new1.php',
dataType : 'json', // Notice json here
data : $("#myform").serialize(), // serializes the form's elements.
success : function (data) {
alert('yeah'); // show response from the php script.
// make changed here
$('input[name="firstname"]').text(data.firstname);
$('input[name="lastname"]').text(data.lastname);
}
});
e.preventDefault(); // avoid to execute the actual submit of the form.
});
solution2
2 2017-01-11 11:46:30
When you use form as a serialize you have to retrieve like this.
Edit your ajax like this :
data: { formData: $("#myform").serialize()},
Then you can retrieve like this in your controller:
parse_str($_POST['formData'], $var);
echo "<pre>";
print_r($var);
exit;
solution3
1 2017-01-11 11:36:32
Change from
alert('yeah'); // show response from the php script.
to
alert(data); // show response from the php script.
solution4
1 2017-01-11 11:42:56
Make some changes in javascript here:
success: function(data)
{
$('#response').html(data); // show response from the php script.
}
And in html code make a div with id response
<div id="response"></div>
solution5
1 2017-01-11 11:46:48
the value firstname, lastname will not display because you called the new1.php via ajax and the data (firstname, lastname and the page code) is returned to java script variable (data) you need to inject the data to your document
Try this
$.ajax({
type: "POST",
url: 'new1.php',
data: $("#myform").serialize(), // serializes the form's elements.
success: function(data) {
document.documentElement.innerHTML = data;
}
});
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