How to set JSON output into UILabel in Swift 3.0 ?

Question

I have these JSON data.

(
        {
        email = "b@p.com.my";
        login = ID001;
        pw = 1234;
    },
        {
        email = "p@d.com.my";
        login = ID002;
        pw = 12345;
    }
)

Right now, I can only print myJSON value in x code output.

My question is, how to display each JSON into UILabel _email, _login, _pw?

Someone said that I need to store as variable and set into UILabel but i don't know how to do it. Appreciate if someone can help me on this matters.

ViewController.swift

import UIKit
class ViewController: UIViewController {
    @IBOutlet var _email: UILabel!
    @IBOutlet var _login: UILabel!
    @IBOutlet var _pw: UILabel!

    override func viewDidLoad() {
        super.viewDidLoad()
        let url = URL(string: "http://localhost/get.php")
        let task = URLSession.shared.dataTask(with: url!) {
            (data, response, error) in
            if error != nil {
                print("Error")
                return
            }
            else {
                if let content = data {
                    do {
                        let myJSON = try JSONSerialization.jsonObject(with: content, options: JSONSerialization.ReadingOptions.mutableContainers) as AnyObject
                        print(myJSON)
                    }
                    catch {}   
                }
            }
        }
        task.resume()
    }
}

Thanks.

Answer 1

EDIT: After the block where you print your myJSON, try this:

for eachItem in myJSON {
if let emailParsed = eachItem["email"] as? String {
    print(emailParsed)
    _email.text = emailParsed 
} 
}

This loop runs between all the dictionaries and This solution could be helpful for you. Please go through it!

Answer 2

Hi Please try this one

   for i..0 < myJson.count { 
      let object = myJson[i] as AnyObject
      if let emailParsed = myJSON["email"] as? String {
         _email.text = emailParsed 
      }     
   }

EDITED

for i..0 < myJson.count { 
      let object = myJson[i] as [String : AnyObject]
      if let emailParsed = myJSON["email"] as? String {
         _email.text = emailParsed 
      }     
   }

Answer 3

It's simple because your json object gives an array of dictionary so first you have to take first object from array and after that you can take the string passing the key

override func viewDidLoad() 
{
  super.viewDidLoad()
  let url = URL(string: "http://localhost/get.php")
  let task = URLSession.shared.dataTask(with: url!) 
             {
             (data, response, error) in
                  if error != nil
                     {
                       print("Error")
                       return
                     }
                  else 
                     {
                       if let content = data 
                          {
                             do {
                                  let myJSON = try JSONSerialization.jsonObject(with: content, options:JSONSerialization.ReadingOptions.mutableContainers) as AnyObject
                                 //   print(myJSON)
                                    for data in myJSON
                                    {
                                        let email = data.1["email"] as? String
                                        _email.text = email

                                    }
                                }
                                catch {}   
                          }
                      }
             }
             task.resume()
      }
}

For batter option you can use some predefined libraries like swiftyJSON. To get best result.