Sorry, I needed to edit my question as I'm actually looking for substrings with more than one character. The suggested answers are good, but mostly work for one character strings.
import panda as pd
test = pd.DataFrame({'A': 'ju1 j4 abjul boy noc s1 asep'.split(),
'B': [1, 2, 3, 4, 5, 6, 7]})
print(test)
A B
0 ju1 1
1 j4 2
2 abjul 3
3 boy 4
4 noc 5
5 s1 6
6 asep 7
I know I can select all the rows that contain 'ju' with
subset = test[test['A'].str.contains('ju')]
print(subset)
A B
0 ju1 1
1 abjul 3
Is there an elegant way to select all rows that contain either 'ju' or 'as'?
This works as suggested below, are there other ways that also work?
ju = test.A.str.contains('ju')
as = test.A.str.contains('as')
subset = test[ju | as]
In [13]: test.loc[test.A.str.contains(r'[js]')]
Out[13]:
A B
0 j1 1
1 j4 2
2 abjul 3
5 s1 6
6 asep 7
option 1
try using str.match
test[test.A.str.match('.*[js].*')]
option 2
set
operations
s = test.A.apply(set)
test[s.sub(set(list('js'))).lt(s)]
option 3
set
operations with numpy
broadcasting
s = test.A.apply(set)
test[(~(np.array([[set(['j'])], [set(['s'])]]) - s.values).astype(bool)).any(0)]
option 4
separate conditions
cond_j = test.A.str.contains('j')
cond_s = test.A.str.contains('s')
test[cond_j | cond_s]
All yield
A B
0 j1 1
1 j4 2
2 abjul 3
5 s1 6
6 asep 7
time testing
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.