how to print the column of a file in unix recursively?

Question

I want to print the columns of a file in unix to a temp file.Below is the code that i have wrote but its not giving proper output.

#!/bin/bash

CURRENT_DATE=`date +'%d%m%Y'`
Temp_Path=/appinfprd/bi/Scripts/IRP/New_Vendors/
IRP_PROJECT/SXM_SFTP/*/INBOUND -type f head -1|xargs -0 ls -al  > "$Temp_Path/Column_$CURRENT_DATE.txt"

Answer 1

Solution with find command only

find \
IRP_PROJECT/SXM_SFTP/*/INBOUND \
-type f \
-exec head -1 {} \; \
 > "$Temp_Path/Column_$CURRENT_DATE.txt"