Question

I try to build a Notification Popup I have for this a script what seems to work but when I add a code I am = getting the numbers 1 2 3 4 from the 4 records from this user-id

I would like to see only the total number (4)

 <?php $q=mysqli_query($conn,"select * from notice where user='".$_SESSION['user']."'"); $rr=mysqli_num_rows($q); if(!$rr) { echo "<h2 style='color:red'>No any notice for You !!!</h2>"; } else { ?> <?php $i=1; while($row=mysqli_fetch_assoc($q)) { echo "<Tr>"; echo "<td>".$i."</td>"; echo "</Tr>"; $i++; } ?> </table> <?php }?>

Answer 1

simply add the echo out of your loop

$i=1;

while($row=mysqli_fetch_assoc($q))
{

$i++;
}
echo "<Tr>";
echo "<td>".$i."</td>";

echo "</Tr>";

Answer 2

Just output the $rr variable, it contains the number of rows.

mysqli_num_rows

UPDATE, example added based on your code:

<?php 
$q=mysqli_query($conn,"select * from notice where user='".$_SESSION['user']."'");
$rr=mysqli_num_rows($q);
if(!$rr)
{
    echo "<h2 style='color:red'>No any notice for You !!!</h2>";
}
else
{
    echo "<h2 style='color:green'>Total Notice for you: $rr</h2>";      
}
?>

Answer 3

Use MySQL's COUNT function..

assuming your user table has a column named id .. try

 $q=mysqli_query($conn,"select COUNT(`id`) as USERS from notice where.... 

Doing this will result in 1 result, so remove your while and just do..

$row=mysqli_fetch_assoc($q);
echo $row['USERS'];