Given a dictionary like this:
dic = {(7, 3): 18.51, (1, 3): 18.751, (5, 6): 34.917, (9, 8): 18.9738}
I want to convert it to a list of tuples like this:
my_list = [(7, 3, 18.51), (1, 3, 18.751), (5, 6, 34.917), (9, 8, 18.9738)]
I could have used a loop but I wonder if there is a neat way to do so instead of loops.
Simply use list(..)
on some generator:
my_list = list(key+(val,) for key,val in dic.items())
This works since:
list(..)
takes as input an iterable and converts it to a list; and key+(val,) for key,val dic.items()
is a generator that takes a pair of key-values of dic
and transforms it into a tuple appending the val
to the key
. Since we use a generator for a list, we can simplify this with list comprehension :
my_list = [key+(val,) for key,val in dic.items()]
Finally mind that the order in which the tuples occur is not fixed this is because the order how a dict
stores elements is not fixed as well.
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