mysql and php syntax error

Question

I am getting MYSQL Error and My 1uery is:

$SQL = "SELECT * FROM `".TBL_DEVICE."` WHERE DEV_STATUS='1' $where ORDER BY DEV_TYPE ASC";

Error is as follows

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ORDER BY DEV_TYPE ASC' at line 1

SELECT * FROM `device` WHERE DEV_STATUS='1' AND DEV_ID = ORDER BY DEV_TYPE ASC

Answer 1

你还没有给 - DEV_ID 赋值

SELECT * FROM `device` WHERE DEV_STATUS='1' AND DEV_ID = '*add here*' ORDER BY DEV_TYPE ASC

Answer 2

Well, at least you printed it out, something most people don't do, and something that makes 97% of these problems obvious :-)

SELECT * FROM `device` WHERE DEV_STATUS='1' AND DEV_ID = ORDER BY ...
                                            \__________/
                                               $where

Your $where variable appears to be incomplete in that it contains AND DEV_ID = but without what you want to compare it with.

You need to fix the code that generates that where sub-clause so that the resulting query is valid.

Answer 3

Your question is no clear enough for me, but in your sql code

$SQL = "SELECT * FROM ".TBL_DEVICE." WHERE DEV_STATUS='1' $where ORDER BY DEV_TYPE ASC";

why you are using $where variable?? and what is it's expected value?

The basic Structure for select all data from a table is :

$SQL = "SELECT * FROM table_name WHERE id = desire_id";

Hope this help

Answer 4

I am assuming that your variable "$where" has this value => "AND DEV_ID =".

$where = "AND DEV_ID =";

first: complete your variable "$where".

$where = "AND DEV_ID = ".your_supposed_to_be_a_value_here.";

second: if you don't mind, change your variable name into something more relative.

third: assumed query

$where = "AND DEV_ID = ".your_supposed_to_be_a_value_here.";
$SQL = "SELECT * FROM `".TBL_DEVICE."` WHERE DEV_STATUS='1' $where ORDER BY DEV_TYPE ASC";