I'm trying to check if a folder exists. If it doesn't, I create it.
I have this code:
if [ $(is_dir "$contaniningdir/run") = "NO"]; then
mkdir "$containingdir/run"
fi
However, I'm getting:
is_dir: command not found
So how what's the correct way of doing this?
You should use
if [ ! -d "$DIRECTORY" ]; then
# your mkdir and other stuff ...
fi
as per this question/answer. . Another relevant question/answer is here .
One of the comments also mentions an important notice:
One thing to keep in mind: [ ! -d "$DIRECTORY" ] will be true either if $DIRECTORY doesn't exist, or if does exist but isn't a directory.
For more you should probably check that other question's page.
is_dir is a PHP function that you probably mixed with bash unintentionally :)
bash is capable of checking for the existence of a directory without external commands:
if [ ! -d "${containingdir}/run" ]; then
mkdir "${containingdir}/run"
fi
!
is negation, -d
checks if the argument exists and is a directory
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