Close file handle in list comprehension

Question

Let's say I want to read in all the lines from a file and store as a list of strings. I can use:

filename = "/path/to/the/file/data.txt"
fileBuf = [line.strip() for line in open(filename, "r")]

My question is, because the file handle is unnamed, how do I close it? Is it closed automatically?

Answer 1

It is probably garbage collected, but recommended way is to use with context. You could even do it in one line:

with open(filename, "r") as f: fileBuf = [line.strip() for line in f]

Answer 2

You can use with statement Code :

with open(FILENAME, 'r') as f:
     fileBuf = [line.strip() for line in f]

Hope this helps !