compare element's of two arrays which are in another array

Question

Checking first 2 elements:

Checking next 2 elements:

I have this array, need to compare each 2 elements

var my_arr = [
           [0,1,2],
           [0,2,1],
           [1,0,2],
           [1,2,0],
           [2,0,1],
           [2,1,0]
         ];

I need to get this as final result. Script must compare every 2 elements of every array and get only one of them

var new_arr = [
           [0,1,2],
           [0,2,1],
         ];

Answer 1

You could use a nested approach with iterating the pattern part with i and j and the part for test with k and l . If two elements are found the array is spliced.

 var array = [[0, 1, 2], [0, 2, 1], [1, 0, 2], [1, 2, 0], [2, 0, 1], [2, 1, 0]], i = 0, j, k, l; while (i < array.length) { j = 0; while (j + 1 < array[i].length) { k = i + 1; test: while (k < array.length) { l = 0; while (l + 1 < array[k].length) { if (array[i][j] === array[k][l] && array[i][j + 1] === array[k][l + 1]) { array.splice(k, 1); continue test; } l++; } k++; } j++; } i++; } console.log(array); 

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