I am having issues trying to figure out how to display all elements in a LinkedList. I could solve this by having an arraylist to track the index of every element, however I would want to solve this without the use of arraylist or arrays.
The following is what I currently have,
public void displayItems()
{
ArrayList<Node> links = new ArrayList<Node>();
links.add(head);
for (int x = 0; x < count; x++)
{
links.add(links.get(x).getLink());
System.out.println(links.get(x).getData());
}
is there a way to display all elements, in a similar method as mentioned above but without the need for arrays or ListIterator?
A few examples how to loop through LinkedList in Java (including one you don't like - using Iterator):
LinkedList<Node> links = new LinkedList<Node>();
links.add(firstNode);
links.add(secondNode);
links.add(thirdNode);
/* For loop */
for(int i = 0; i < links.size(); i++) {
System.out.println(links.get(i).getLink());
}
/* For-each loop */
for(Node node: links) {
System.out.println(node.getLink());
}
/* While Loop*/
int i = 0;
while (links.size() > i) {
System.out.println(links.get(i++).getLink());
}
/* Iterator */
Iterator<Node> it = links.iterator();
while (it.hasNext()) {
System.out.println(it.next().getLink());
}
You can use an integer as a global variable, while inserting data into Linked List increment this variable.
Write a method in LinkedList class with parameter position. Here loop upto the position, get the data and return the same.
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