MVC model is null when posting json in ASP.Net Core

Question

All relevant code:

//JSON data
var dataType = 'application/json; charset=utf-8';
var data = {
    FirstName: 'Andrew',
    LastName: 'Lock',
    Age: 31
}

console.log('Submitting form...');
$.ajax({
    type: 'POST',
    url: '/Diary/Save',
    dataType: 'json',
    contentType: dataType,
    data: data,
    success: function (result) {
        console.log('Data received: ');
        console.log(result);
    }
});


[HttpPost]
public IActionResult Save([FromBody] Person person)
{
    return Json(person);
}



public class Person
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public int Age { get; set; }
}

"person" in the Save method is always null. This should work...it feels perhaps like a settings issue? Do I need to make changes here:

 services.AddMvc(options =>
        {
        });

Answer 1

您需要对要发送到服务器的数据进行字符串化，以将其转换为JSON，因为这是您指示的内容类型标头：

data: JSON.stringify(data)

Answer 2

Please Try This Solution :

var data = {firstname : 'ali', lastname: 'alavi', age: 31};
var formData = new FormData();
formData.append('data',JSON.stringify(data));

$.ajax({
        type: "POST",        
        url: controllerUrl, //something like ~/[ControllerName]/[ActionName]
        data: formData,
        contentType: "application/json; charset=utf-8",
        dataType: "json",
        processData: false,
        contentType: false,
        success: function (data) {
            if (data.success)
                // ...
            else
                // ...
        },
        error: function () {
            // log error ...
        }
    });

using Newtonsoft.Json;
.
.
.
 [HttpPost]
 public JsonResult CreateServicesPost(string data)
 {
     var personModel = new PersonModel();
     personModel = JsonConvert.DeserializeObject<PersonModel>(data);
      // ...
 }

public class CreateServicePostModel
{
        public string Firstname{ get; set; }
        public string Lastname { get; set; }
        public int Age { get; set; }
}