How to use a dictionary to print its partner value

Question

Not sure if the title is specific enough.

words = ['sense', 'The', 'makes', 'sentence', 'perfect', 'sense', 'now']
numbers = ['1', '2', '3', '4', '5', '6']
dictionary = dict(zip(numbers, words))
print(dictionary)
correctorder = ['2', '4', '7', '3', '5', '6']

I'm simply trying to figure out how exactly I can print specific values from the dictionary using the correctorder array so that the sentence makes sense.

Answer 1

You can just iterate over correctorder and get the corresponding dict value, then join the result together.

' '.join(dictionary[ele] for ele in correctorder)

This is assuming that you fix numbers to include '7' at the end.

>>> ' '.join(dictionary[ele] for ele in correctorder)
'The sentence now makes perfect sense'

Answer 2

What you want is this.

for i in correctorder: 
    print dictionary[i]," ",

Short and simple. As Mitch said, fix the 7 though.

Answer 3

You could use operator.itemgetter to avoid an explicit loop:

>>> from operator import itemgetter
>>> print(itemgetter(*correctorder)(dictionary))

To concatenate this simply use str.join :

>>> ' '.join(itemgetter(*correctorder)(dictionary))