How to replace +91 using regex pattern?
Question
Get from https://www.w3schools.com/jsref/tryit.asp?filename=tryjsref_replace2
Now I want to change +91 in a string. From https://www.w3schools.com/jsref/tryit.asp?filename=tryjsref_replace2
<!DOCTYPE html>
<html>
<body>
<p>Click the button to replace "blue" with "red" in the paragraph below:</p>
<p id="demo">Mr Blue has a blue house and a blue car.</p>
<button onclick="myFunction()">Try it</button>
<script>
function myFunction() {
var str = document.getElementById("demo").innerHTML;
var res = str.replace(/blue/g, "red");
document.getElementById("demo").innerHTML = res;
}
</script>
</body>
</html>
Lets consider following string.
String:- Hi My number is +919090909090 and +9190820209282 and ... etc.
I want result like: Hi My number is +91 - 9090909090 and +91 - 90820209282 and ... etc.
But when I using regex pattern, it seems to through an error when I am using str.replace(/blue/g, "red");
Invalid regular expression: /+91/: Nothing to repeat"
2 answers
solution1
4 ACCPTED 2017-02-23 11:05:25
The + sign is a special character in regex
Quantifier — Matches between one and unlimited times, as many times as possible, giving back as needed (greedy) (from regex101.com )
It needs to be escaped if you want to match against the string literal + :
/\+91/
will match.
An example replacement like you want it to have would be (again from regex101.com )
const regex = /(\\+91)/g; const str = `+911147005555, +911147005556, +919999973703`; const subst = `\\$1 - `; // The substituted value will be contained in the result variable const result = str.replace(regex, subst); console.log('Substitution result: ', result);
solution2
0 2017-02-24 08:19:01
$scope.spacehypheninPhoneNumber = function () {
const regex = /^(\+91)/;
const strs = "+911147005555, +911147005556, +919999973703";
const subst = "\$1 - ";
const space = " ";
var replaced = strs.replace(/ /g, '');
var getAllNumbers = replaced.split(',');
var finalResult = '';
for (var i = 0; i < getAllNumbers.length; i++) {
console.log('Substitution result: ', getAllNumbers[i]);
const result = getAllNumbers[i].replace(regex, subst);
console.log('Substitution result: ', result);
if(i==0){
finalResult += space+ result;
}else{
finalResult += ","+space+ result;
}
}
console.log('Final Output that I want:'+finalResult );
}
Its working fine. I am using the regex pattern which @baao told me. Then by using loop I concatenate the result
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