MySql: Sort 2 columns by certain conditions

Question

I have community table with following columns as shown below:

I need to sort table by " ftr_order " and " isFeatured " columns in a certain way that it displays data in the following order:

ftr_order | isFeatured

   2      |   yes
   1      |   no
   2      |   no
   3      |   no
   4      |   no
   5      |   no
   6      |   no
   0      |   no
   NULL   |   no
   NULL   |   no
   NULL   |   no

ftr_order should sort data in ascending order. 0 and NULL values should come at the bottom of the table. I have tried the following query, this resolved it to some extent, but I need to set priority ie

i) First Priority : If isFeatured is yes then show it on the top.

ii) Second Priority : Sort ftr_order in ascending order

** Note: If ftr_order is 0 or NULL then display data at bottom.

SELECT * FROM community ORDER BY if(ftr_order = 0 or ftr_order is null,1,0), ftr_order ASC, community_description ASC

This displays the following output:

Here you can see that ftr_order has been sorted out correctly but one thing is missing here, ID number 7 should be listed on the top of the table as this row has column isFeatured ='yes'. In order to bring this row on the top I tried to resolve it by writing down the query:

SELECT * FROM community ORDER BY if(ftr_order = 0 or ftr_order is null,1,0 or isFeatured='yes'), ftr_order ASC, community_description ASC

You can see the following output is generated and you can also analyze what issue is still left. ID number 7 should be listed on the top of the table, but here ID number 7 is listed at the bottom of the table. Therefore I need to shift it on the top. Please help me out to resolve this issue. Thanks in advance!

Answer 1

SELECT * FROM community ORDER BY isfeatured desc, ftr_order ASC, community_description ASC

You can try like this if isfeatured has only yes/no make it simple

Answer 2

Finally I got answer to my own question, solution is as follows:

SELECT * from (SELECT * FROM `community` ORDER BY if( ftr_order =0 OR ftr_order IS NULL , 1, 0 ) , ftr_order ASC , community_description ASC) as community ORDER BY CASE WHEN isFeatured ='yes' then isFeatured END desc

Following output will be generated:

Here isFeatured ='yes' is at the top and rest of the data is order by ftr_order ascending where NULL and 0 will come at the end.

ftr_order | isFeatured

   2      |   yes
   1      |   no
   2      |   no
   3      |   no
   4      |   no
   5      |   no
   6      |   no
   0      |   no
   NULL   |   no
   NULL   |   no
   NULL   |   no