Python Intended Block error

Question

I am sorry but i have a problem that i dont understand...

def login_screen():
    print(30 * "-")
    print("   LOGIN")
    print(30 * "-")
    username = print("Please enter your username: ")
    password = print("Please enter your password: ")
        with open('logins.txt', 'r') as csvfile:
            loginreader = csv.reader(csvfile, delimiter=',', quotechar= None)
            for codes in loginreader:
                if len(codes) == L_LEN:
                    if codes[L_USERNAME] == username and codes[L_PASSWORD] == password and codes[L_ADMIN] == "Yes":
                        admin_console()
                    elif username == row[L_USERNAME] and password == row[PASSWORD] and row[L_ADMIN] == "No":
                        #Temp normal console here
                    else:
                        clearscreen()
                        error_head()
                        print("Unknown account")
                        input("Press [ENTER] To continue...")
                        login_screen()
                elif len(codes) != M_LEN:
                    next(csvfile, None)

So the problem is that it comes with the following error:

  File "G:\Python\DatabaseStandardRewrite\Login.py", line 49
else:
   ^

IndentationError: expected an indented block

But i dont get it! (Yes, all the other things are defined in the rest of the document!

Does anyone of you see my mistake?

Natan

Answer 1

Python does not permit blocks to be empty; you need at least one statement, and a comment does not count. So in the elif block before your else , you should put pass .

            elif username == row[L_USERNAME] and password == row[PASSWORD] and row[L_ADMIN] == "No":
                #Temp normal console here
                pass
            else:
                clearscreen()